Hmm, thanks! In my mind, working with digital/technology my self, the sine waves "should" not matter as long as they remain readable as ones and zeros, which they do, as Alpha Audio also shown. There is never packet drops. The data is buffered before the DAC step so the sinewaves should be nullified anyway, i am thinking. Maybe i am misunderstanding your explanation but in my mind it has to do with noise :-), as you know i believe, and then the the core throttle must also remove noise some how?

I read up a bit and i now understand that the sinewave is in fact the analogue part (ground plane?), from what i understand. Then i can see that it could make a difference and somehow influence the DAC performance.

With the sinewave I meant the data waveform. In fact it's not a sine wave. (see reply 197275 and 197277) On this waveform you can see another tiny waveform on top of it. That tiny waveform on top is not data, it's noise, but there will also be noise that is so fast that my scope can't picture it. Normally the noise that you can't see will be smoothed first, but the tiny waveform that you can see on top of the actual waveform will be smoothed a bit as well by the ferrite (inductor). The more windings we make the more noise we cancel, until we cancel the main waveform as well.

What we can't do with an inductor is repairing the waveform build itself.

With a high grade powersupply we can reduce noise in the first place by not creating it. Also the waveform builds are a lot better. I guess that this waveform is also driving the crystal of the receiving switch. The stronger the drive the less the flexibility of the receiving switch to talk with other devices. Still each device should capture the waveform that is received and sent by one crystal. I think this will cause a less perfect shape of the waveform itself.

I'm not sure if my thought about this is correct, but I think it can be explained best by a R2R Dac. With a R2R dac a dataword will find a resistor for each bit in the word. This way the dataword will be converted into an analog signal. I think everyone could understand that the width and shape of each bit going through the resistors to create an analog signal matters a lot.

I also think this matter on a conventional dac chip. And indeed still everything can be bit perfect at the same time 🙂

I figured 🙂

The more we know the more it seems we can't understand. Speaking of myself of course. I've been discussing ethernet for over a decade now and I'm still learning how little I know. For me it helps a lot when people with knowledge think with me. So thanks!

Wrong position. This was a reply on 197141

In addition to the above. About driving a crystal of the receiving switch or device. Every ethernet device has a galvanic isolator transformer on each port. So receiving data is slightly delayed. This will also be the case for the crystal that will clock in the data (At least according to a measurement interpretation). At the moment the switch or ethernet device will change talking to another device it should fast synchronize to this other device to make sure the data can be received in good shape.

Please correct me, because I most certainly are off track now 🙂